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Question:

A mass M attached to a horizontal spring, executes SHM with amplitude A1. When the mass M passes through its mean position, then a smaller mass m is placed over it and both of them move together with amplitude A2. The ratio of (A1/A2) is:

M+m

√M+m

√MM+m

MM+m

Solution:

Energy of simple harmonic oscillator is constant.
1/2 × Mω²A₁² = 1/2(m+M)ω²A₂²