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Question:

A metal on combustion in excess air forms X. X upon hydrolysis with water yields H2O2 and O2 along with another product. The metal is: Na Li Mg Rb

Na

Mg

Rb

Li

Solution:

The metal is Rb. Rb + O2(excess) → RbO2
Here product X is RbO2.
2RbO2 + 2H2O → 2RbOH + H2O2 + O2.