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Question:

A number x is chosen at random from the set 1, 2, 3, 4, ..., 100. Define the event A = the chosen number x satisfies (x-10)(x-50)(x-100) ≥ 0. Then P(A) is:

0.71

0.70

0.51

0.20

Solution:

(x-10)(x-50)(x-100) ≥ 0
Events ⇒ Number from 10 to 29 + Numbers from 50 to 100
⇒ 20 + 51 = 71.
Probability = 71/100 = 0.71