A parallel plate capacitor of capacitance 20µF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively.
60µA,zero
zero,60µA
60µA,60µA
zero , zero
Solution:
Correct option is B. 60µA, 60µA Capacitance of capacitor C=20µF=20×10⁻⁶ F Rate of change of potential is,(dV/dt)=3v/s ⇒q=CV ⇒dq/dt=CdV/dt ic=20×10⁻⁶×3=60×10⁻⁶A=60µA As we know that id=iC=60µA