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Question:

A parallel plate capacitor of capacitance 20µF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively.

60µA,zero

zero,60µA

60µA,60µA

zero , zero

Solution:

Correct option is B. 60µA, 60µA
Capacitance of capacitor C=20µF=20×10⁻⁶ F
Rate of change of potential is,(dV/dt)=3v/s
⇒q=CV
⇒dq/dt=CdV/dt
ic=20×10⁻⁶×3=60×10⁻⁶A=60µA
As we know that id=iC=60µA