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Question:

A particle moves from a point (2î+5ĵ) to (4ĵ+3k̂) when a force of (4î+3ĵ)N is applied. How much work has been done by the force?

2J

-8J

-11J

5J

Solution:

Displacement of the particle →S=(4ĵ+3k̂) − (2î+5ĵ) = -2î -ĵ +3k̂
Force acting on the particle →F=4î+3ĵ
∴Work done W= →F.→S = (4î+3ĵ) (-2î -ĵ +3k̂) = -8 + (-3) = -11J