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Question:

A particle of mass m is moving in a straight line with momentum p. Starting at time t=0, a force F=kt acts in the same direction on the moving particle during time interval T so that its momentum changes from p to 3p. Here k is a constant. The value of T is?

2√kp

√2kp

2√pk

√2pk

Solution:

The correct option is A
2√pk
dp/dt = F = kt
∫₃ₚpdP = ∫0T kt dt
2p = kT²/2
T = 2√pk.