A photoelectric surface is illuminated successively by monochromatic light of wavelengths λ and λ2. If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times that in the first case, the work function of the surface is :
3hcλ
hcλ
hc2λ
hc3λ
Solution:
The correct option is A hc2λ K.Eλ=hcλ−Φ K.Eλ/2=hcλ/2−Φ K.Eλ/2=3(K.Eλ)→Φ=hc2λ