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Question:

A photon is incident having frequency 1x1014 sec-1. Threshold frequency of metal is 5x1013 sec-1. Find the kinetic energy of the ejected electron?

3.3x10-19J

6.6x10-19J

3.3x10-20J

6.6x10-20J

Solution:

We have, hν = hν0 + KE ⇒ KE = h(ν - ν0)
From the given values of respective frequencies and the value of Planck's constant, we have,
KE = 3.313 x 10-20J