Eduprobe
Question:
A piece of ice (heat capacity=2100Jkg⁻¹°C⁻¹ and latent heat=3.36×10⁵Jkg⁻¹) of mass m grams is at -9°C at atmospheric pressure. It is given 420J of heat so that the ice starts melting. Finally when the ice-water mixture is in equilibrium, it is found that 1 gm of ice has melted. Assuming there is no other heat exchange in the process, the value of m is?
9
8
7
6
Solution:
Heat=latent heat+Heat required to raise temp
Q=mL+mCpΔT
420=(m×2100×5+1×3.36×10⁵)×10⁻³ where m is in gm.
m=8g