A piggy bank contains hundred 50p coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50p coin ?<p></p>

Total number of coins in the piggy bank = 100 + 50 + 20 + 10 = 180
i) Probability (50p coin) = number of 50p coins / total number of coins = 100 / 180
P(50p coin) = 5/9
ii) Number of Rs. 5 coins = 10
Number of coins which are not Rs. 5 = 170
Probability (coin not being Rs. 5) = 170 / 180 = 17/18

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Question:

A piggy bank contains hundred 50p coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50p coin ?

Solution: