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Question:

A plane which bisects the angle between the two given planes 2x-y+2z-4=0 and x+2y+2z-2=0, passes through the point (2,4,1), (2,-4,1), (1,4,-1), (1,-4,1)

(2,-4,1)

(1,4,-1)

(1,-4,1)

(2,4,1)

Solution:

The correct option is B(2,-4,1)
Equation of bisector of angle 2x-y+2z-4=0 and x+2y+2z-2=0
(2x-y+2z-4)/3 = ±(x+2y+2z-2)/3
(+): gives x-3y=2
(-): gives 3x+y+4z=6
Therefore option (ii) satisfy.