A point on the straight line 3x+5t=15 which is equidistant from the coordinate axes lies only on:

Correct option is A. 1stand2ndquadrants
Now ,|15−3t5|=|t| ⇒15−3t5=t or 15−3t5=−t
∴t=158 or t=−152
So,P(158,158)∈1stquadrant or P(−152,152)∈2ndquadrant