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Question:

A reaction at 1 bar is non-spontaneous at low temperature but becomes spontaneous at high temperature. Identify the correct statement about the reaction among the following: both ΔH and ΔS are negative; both ΔH and ΔS are positive; ΔH is negative while ΔS is positive; ΔH is positive while ΔS is negative

ΔH is positive while ΔS is negative

ΔH is negative while ΔS is positive

both ΔH and ΔS are positive

both ΔH and ΔS are negative

Solution:

Both ΔH and ΔS are positive
ΔG = ΔH - TΔS