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Question:

A rectangular conductor LMNO is placed in a uniform magnetic field of 0.5 T. The field is directed perpendicular to the plane of the conductor. When the arm MN of length 20 cm is moved towards the left with a velocity of 10 ms⁻¹, calculate the emf induced in the arm. Given the resistance of the arm to be 5 Ω (assuming that other arms are of negligible resistance), find the value of the current in the arm.

Solution:

The emf induced in the loop = ε = dΦ/dt = d(Blx)/dt = Bl(-dx/dt) = Blv = 0.5 × 0.2 × 10 = 1V

The current in the arm is given by Ohm's law:
I = V/R = 1V / 5Ω = 0.2A