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Question:

A refrigerator works between 40°C and 300°C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is: (Take 1 cal = 4.2 Joules)

2.365W

236.5W

23.65W

2365W

Solution:

β=Q/W = T₂/(T₁-T₂)
⇒600×4.2/W = 303/(303-273)
⇒W = 236.5 J
Power, P = W/t = 236.5/1 = 236.5 Watt