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Question:

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume of this process is TVx = constant, then x is:

25

35

53

23

Solution:

The correct option is B
For adiabatic process : TVγ-1 = constant
For diatomic process : γ = 7/5
∴ x = 2/5