2tanθ
3tanθ
tanθ
tan2θ
Free body diagram is shown in the figure. Pseudo force on the object is 2mg in the downward direction as seen from the rocket frame of reference. Normal force in the direction perpendicular to the inclined plane. N=3mgcos(θ) Maximum frictional force in the direction along the plane, Fr=μminN ∴Fr=3μminmgcos(θ) This should balance the force on the block along the downward direction of plane. 3mgsin(θ)=3μminmgcos(θ) μmin=tan(θ)