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Question:

A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

Wdx

W(d−x)d

W(d−x)/x

Wxd

Solution:

Taking moment about point B
NAd - W(d-x) = 0
NA = W(d-x)/d
hence correct answer is option B.