A sample of NaClO3 is converted by heat to NaCl with a loss of 0.16g of oxygen. The residue is dissolved in water and precipitated as AgCl. The mass of AgCl (in g) obtained will be: (Given: Molar mass of AgCl=143.5g/mol) 0.48, 0.41, 0.35, 0.54

The molar mass of O2 = 32g/mol
0.16g of oxygen = 0.16g / 32g/mol = 0.005mol
2NaClO3 → 2NaCl + 3O2
3 moles of O2 = 2 moles of NaCl = 2 moles of AgCl.
0.005 moles of O2 = 0.005 × (2/3) = 0.003333 moles of AgCl.
Molar mass of AgCl = 143.5g/mol
The mass of AgCl (in g) obtained will be = 143.5g/mol × 0.003333mol = 0.48g.