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Question:

A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading: 0 mm. Circular scale reading: 52 divisions. Given that 1 mm on the main scale corresponds to 100 divisions of the circular scale. The diameter of the wire from the above data is: ?

0.052 cm

0.026 cm

0.52 cm

0.005 cm

Solution:

Here, pitch of the screw gauge, p = 1 mm
Number of circular divisions, n = 100
Thus, least count LC = p/n = 1/100 = 0.01 mm = 0.001 cm
Diameter of the wire = MSR + (CSR × LC) = 0 + (52 × 0.001cm) = 0.052 cm