800Hz
885Hz
765Hz
838Hz
The general formula for apparent frequency is f'=v±vO/v∓vS
As observer is at rest so vO=0
Since the source moves towards cliff, i.e., effectively the source moves towards the observer (the sound being heard through echo), so vS taken as -vS=15 m/s
Thus, f'=v/(v-vS)f = 330/(330-15)800 = 838 Hz