(0,0)
(25,25√3)
(125/3,25/√3)
(50√3,25)
Let final image be at a distance x from the lens to its right and between the lens and the mirror.
y50−x=tan60°=√3
y+√3x=50√3
This is satisfied by option A and D.
A and B both option satisfy this,
Size of image > Size of object
√y²+(50−x)²sin30°>25sin30°
y²+(50−x)²>625
Checking option D, 625(3)+625=4(625)>625
Answer is option D.