A solid iron pole consists of a cylinder of height 220cm and base diameter 24cm, which is surmounted by another cylinder of height 60cm and radius 8cm. Find the mass of the pole, given that 1cm³ of iron has approximately 8g mass. (Use π= 3.14)

Height (h1) of larger cylinder = 220cm
Radius (r1) of larger cylinder = 24/2 = 12cm
Height (h2) of smaller cylinder = 60cm
Radius (r2) of smaller cylinder = 8cm
Total volume of pole = Volume of larger cylinder + Volume of smaller cylinder
= πr₁²h₁ + πr₂²h₂
= (π(12)² × 220) + (π(8)² × 60)
= π[144 × 220 + 64 × 60]
= 3.14[31680 + 3840]
= 3.14 × 35520
= 111532.8cm³
Mass of 1cm³ iron = 8g
Mass of 111532.8cm³ iron = 111532.8 × 8 = 892262.4g