A solid sphere and solid cylinder of identical radii approach an incline with the same linear velocity. Both roll without slipping all throughout. The two climb maximum heights hsph and hcyl on the incline. The ratio hsph/hcyl is given by:
1415
25
45
1
Solution:
Correct option is A. 14/15 for solid sphere 1/2mv² + 1/2.(2/5)mR².v²/R² = mghsph for solid sylinder 1/2mv² + 1/2.(1/2)mR².v²/R² = mghcyl. ⇒hsph/hcyl = 7/5 3/2 = 14/15