A solution is prepared by dissolving 10 g of non-volatile solute in 200 g of water. It has a vapor pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute. (Vapor pressure of pure water at 308 K = 32 mm Hg)

According to Raoult's law,

(p₀ - p) / p₀ = (w × M) / (m × W)

Where,
p₀ is the vapor pressure of pure water
p is the vapor pressure of the solution
w is the weight of the solute
m is the molecular weight of the solute
W is the molecular weight of the solvent

Substituting the given values:

(32 - 31.84) / 32 = (10 × 18) / (m × 200)

=> 0.016 / 32 = 180 / (m × 200)

=> m = (180 × 32) / (200 × 0.16) = 180

Therefore, the molar mass of the solute is 180 g/mol.