Eduprobe
Question:
A speaks truth in 60% of the cases.
Solution:
Given:
P(AT)=60/100, P(AC)=40/100
P(BT)=90/100, P(BC)=10/100
P(contradiction)=60/100 × 10/100 + 40/100 × 90/100 = 600/10000 + 3600/10000 = 600+3600/10000 = 4200/10000 = 42%
Given:
P(AT)=60/100, P(AC)=40/100
P(BT)=90/100, P(BC)=10/100
P(contradiction)=60/100 × 10/100 + 40/100 × 90/100 = 600/10000 + 3600/10000 = 600+3600/10000 = 4200/10000 = 42%