A speeding motorcyclist sees a traffic jam ahead of him. He slows down to 36 km/hour. He finds that traffic has eased and a car moving ahead of him at 18 km/hour is honking at a frequency of 1392 Hz. If the speed of sound is 343 m/s, the frequency of the honk as heard by him will be:
1372 Hz
1412 Hz
1454 Hz
1332 Hz
Solution:
Apparent frequency heard by the observer is f'=f₀(V-V₀/V-Vₛ) f'=(1392)(343-(5)/343-(18/3.6))=1412Hz