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Question:

A speeding motorcyclist sees a traffic jam ahead of him. He slows down to 36 km/hour. He finds that traffic has eased and a car moving ahead of him at 18 km/hour is honking at a frequency of 1392 Hz. If the speed of sound is 343 m/s, the frequency of the honk as heard by him will be:

1372 Hz

1412 Hz

1454 Hz

1332 Hz

Solution:

Apparent frequency heard by the observer is
f'=f₀(V-V₀/V-Vₛ)
f'=(1392)(343-(5)/343-(18/3.6))=1412Hz