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Question:

A stationary source is emitting sound at a fixed frequency f0, which is reflected by two cars approaching the source. The difference between the frequencies of sound reflected from the cars is 1.2 Hz.

Solution:

Let the speed of the cars be v1 and v2.
Frequency received by the car, f1 = (v/(v-v1))f0
Frequency reflected by car, f2 = ((v+v2)/(v))(v/(v-v1))f0
Δf = f'2 - f1 = ((v+v2)/(v-v1) - v/(v-v1))f0
Solving we get:
Δf = (2vv2/(v-v1))f0
Equating this Δf to 1.2f0/100 we get, v2 - v1 = 7