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Question:

A stone is released from the top of a tower of height 19.6m. Calculate its final velocity just before touching the ground.

Solution:

Given : Height of the tower H=19.6m
Initial velocity of the stone u=0
Acceleration a=g=9.8ms⁻²;
Let the final velocity of the stone be v
Using, v²−u²=2aH
v²−0=2(9.8)×19.6
⇒v=19.6ms⁻¹;