A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:
92±5.0 s
92±1.8 s
92±2 s
92±3 s
Solution:
Sum of all observation=90+91+95+92=368 Average=368/4=92 Sum of modulus errors=2+1+3+0=6 Average error=6/4=1.5, rounded off to 2. Final answer=(92±2) s