A student weighed some raisins and recorded the weight as 'x'. She then soaked the raisins in distilled water. After about 2 hours she removed the raisins, wiped them dry and weighed again and recorded that as 'y'. The percentage of water absorbed by raisins may be determined using which relationship?

Let x be the initial weight of the raisins.
Let y be the weight of the raisins after soaking in water.
The weight of the water absorbed is (y - x).
The percentage of water absorbed is given by the formula:
Percentage of water absorbed = (Weight of water absorbed / Initial weight of raisins) × 100
Percentage of water absorbed = ((y - x) / x) × 100
Therefore, the correct relationship is (y - x) × 100 / x or (y-x)/x * 100

Option A: y−xy×100 is incorrect. It's missing a set of parentheses, resulting in an incorrect calculation.
Option B: y−xx×1100 is incorrect. The denominator is incorrect and an extra 1 is included in the formula.
Option C: (y−x)×100 is incorrect. It represents the weight of absorbed water, not the percentage.
Option D: y−xx×100 is the correct answer. This correctly calculates the percentage of water absorbed relative to the initial weight of the raisins.