A thin uniform rod of length l and mass m is swinging freely about a horizontal axis passing through its end. Its maximum angular speed is ω. Its centre of mass rises to a maximum height of :
l2 ω2/2g
l2 ω2/6g
l2 ω2/3g
l2 ω2/8g
Solution:
By conservation of energy, 1/2(ml2/3)ω2 = mgh h = ω2 l2/6g