A transformer consists of 500 turns in the primary coil and 10 turns in a secondary coil with the load of 10Ω. Find out current in the primary coil when the voltage across the secondary coil is 50 V.

Correct option is B. 1A
As we know that ,
VP/VS = NP/NS
Where VP is the voltage across primary side
VS is the voltage across secondary side
VP/VS = 500/10
VP = 2500
is = VS/R = 50/10 = 5A
ip/is = VS/VP
ip*5 = 500/2500
Current across primary side, ip = 1/5 * 5 = 1A.