A transistor is connected in common emitter (CE) configuration. The collector supply is 8V and the voltage drop across a resistor of 800Ω in the collector circuit is 0.8 V. If the current gain factor (α) is 0.96, then the change in base current is

The collector current, IC = VCE/RE = 0.8V/800Ω = 1mA
The current gain, β = IC/IB
Since, β = α/(1-α) = 0.96/(1-0.96) = 24
Hence, IB = IC/β = 1/24 mA ≈ 0.0416 mA ≈ 41.6 µA. However, none of the options match this. There seems to be an error in either the question or the provided solution. Let's re-examine. The calculation of collector current is correct: IC = 0.8V / 800Ω = 0.001A = 1mA. If β = α / (1 - α) = 0.96 / (1 - 0.96) = 24, then IB = IC / β = 1mA / 24 = 0.04167 mA ≈ 41.67 µA. The provided solution shows IB = 124mA, which is a significant discrepancy. The provided solution contains an error.