If this experiment is performed in a lift going up with a constant acceleration, then h decreases.
h is proportional to contact angle θ
For a given material of the capillary tube, h is independent of σ.
For a given material of the capillary tube, h decreases with increase in r
2σR = ρgh [R → Radius of meniscus]
h = 2σR/ρg
R = rcosθ [r → radius of capillary; θ → contact angle]
h = 2σcosθ/ρgr
(A) For given material, θ → constant
h ∝ 1/r
(B) h depends on σ
(C) If lift is going up with constant acceleration, geff = (g+a)
h = 2σcosθ/ρ(g+a)r which means h decreases
(D) h is proportional to cosθ, NOT θ