m,1x2
m,x2
m,1x
m,x
Let, 'l' and 'M' be the length and mass of rod.
for equilibrium, taking moment about X, we get
m × x = M × (l/2 - x)
this can be written as,
m = (M l/2) (1/x) - M
comparing with straight line equation, y = mx + c
we can say that, m ∝ 1/x