A uniform sphere of mass 500 g rolls without slipping on a plane surface so that its centre moves at a speed of 0.02 m/s. The total kinetic energy of rolling sphere would be (in J)

The total kinetic energy of rolling sphere=Kinetic energy of translation+Kinetic energy of rotation
K=1/2mv² + 1/2Iω²
Since the sphere rolls without slipping, v=Rω
⇒K=1/2mv² + 1/2(2/5mR² )ω² = 1/2mv² + 1/5mv² = 7/10mv²
=7/10 × 0.5 × 0.02² kgm²/s²
=1.4 × 10⁻⁴ J