A uniformly charged ring of radius 3a and total charge q is placed in the xy-plane centered at the origin. A point charge q is moving towards the ring along the z-axis and has speed u at z = -4a. The minimum value of u such that it crosses the origin is:
4kq²/16ma
4kq²/15ma
14pq²/24ma²
4qk²/75ma
Solution:
Correct option is B. 4kq²/15ma Ui + Ki = Uf + Kf kq²/√(16a² + 9a²) + 1/2mv² = kq²/3a 1/2mv² = kq²(1/(3a) - 1/√(16a² + 9a²)) 1/2mv² = kq²(1/(3a) - 1/5a) = 2kq²/15a v = √(4kq²/15ma) u = 4kq²/15ma