L(1+13MgπYR²)
L(1+29MgπYR²)
L(1+19MgπYR²)
L(1+23MgπYR²)
Take a cross section at distance x from the bottom, hence at this point, r = 3R − x/L 2R. Mgπr² = Y dy/dx = Mgπ(3R − x/L 2R)² where dy is elongation of the portion dx. Integrating this equation for x in 0 to L, we get, y = L(1+13MgπYR²)