7π24
π9
π18
7π36
Correct option is C. π9R1→R1−R2|1−1;0cos2θ1+sin2θ4cos6θcos2θsin2θ1+4cos6θ|=0R2→R2−R3|1−1;001−1;cos2θsin2θ1+4cos6θ|=0→(1+4cos6θ)+sin2θ+1(cos2θ)=01+2cos6θ=0→cos6θ=−1/2;6θ=2π3→θ=π9.