A vessel of one litre capacity containing 1 mole of SO3 is heated till a state of equilibrium is attained. 2SO3(g)⇌2SO2(g)+O2(g) At equilibrium, 0.6 moles of SO2 had formed. The value of equilibrium constant is:
0.18
0.36
0.45
0.68
Solution:
2SO3(g)⇌2SO2(g)+O2(g) Initial conc. 1.0 mole 0.0 mole 0.0 mole Equilibrium 0.4 mole 0.6 mole 0.3 mole ⇒Equilibrium constant is given by K=[SO2]2[O2]/[SO3]2=(0.6)2(0.3)/(0.4)2=0.675=0.68 Hence, the correct option is D