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Question:

A voltage V = V₀sin(ωt) is applied to a series LCR circuit. Derive the expression for the average power dissipated over a cycle. Under what condition is (i) no power dissipated even though the current flows through the circuit, (ii) maximum power dissipated in the circuit?

Solution:

Power factor of the circuit is given by: cosφ = R/Z = R/√(R² + (ωL - 1/ωC)²)
Current flowing in the circuit is given by: I = V/Z = V₀sin(ωt)/Z
Instantaneous real power dissipated in the circuit is: P = I²R = V₀²sin²(ωt)R/Z²
Average power dissipated in a cycle is given by:

= ∫₀²π/ω Pdt / ∫₀²π/ω dt = (V₀²R/Z²) x (2π/ω) ∫₀²π/ω (1 - cos(2ωt))dt

= VrmsIrmscos(φ)
(i) No power is dissipated when P = 0
This implies cosφ = 0
φ = π/2
That is the circuit is purely inductive or capacitive
(ii) Maximum power is dissipated when P is maximum.
This implies cosφ = 1
φ = 0
Circuit is purely resistive.