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Question:

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v, the total area around the fountain that gets wet is: ?

πv²/g²

πv⁴/g²

πv²/g

πv⁴/2g²

Solution:

As we know that
A = πRmax² (1)
Maximum Range = Rmax = v²/g (2)
From (1) and (2) we get,
A = πv⁴/g².