A wave travelling in the +ve x-direction having displacement along y-direction as 1 m, wavelength 2πm and frequency of 1πHz is represented by:

The general equation of a wave travelling in the positive x-direction is given by:
y = A sin(kx - ωt)
where:

• A is the amplitude of the wave
• k is the wave number (k = 2π/λ, where λ is the wavelength)
• ω is the angular frequency (ω = 2πf, where f is the frequency)
• x is the position
• t is the time
  Given that the amplitude A = 1 m, wavelength λ = 2π m, and frequency f = π Hz, we can calculate the wave number and angular frequency:
  k = 2π/λ = 2π/(2π) = 1
  ω = 2πf = 2π(π) = 2π²
  Substituting these values into the general equation, we get:
  y = 1 sin(1x - 2π²t) = sin(x - 2π²t)
  However, none of the given options match this equation exactly. Let's re-examine the given parameters. The question states that the frequency is 1π Hz, which is π Hz. Using this corrected frequency:
  ω = 2πf = 2π(π) = 2π²
  This doesn't match any of the options. Let's check if there's an error in the given options. Option B is the closest if we assume the frequency is simply π.
  If we use ω = 2πf = 2π(1π) = 2π and k = 2π/2π = 1, then the equation would be:
  y = sin(x - t) which is close to option A
  If we use ω = 2π(1) = 2π and k = 2π/2π = 1 then we get y = sin(x - t) which is option A, but the frequency is given as π and not 1. The wavelength is 2πm and frequency is πHz. Then k=1 and ω=2π² which isn’t present. Let's assume there's a mistake in the question or options. The correct equation should be y = sin(x - 2π²t) or some variation considering that π is approximately 3.14, the options are not matching the exact formula. Option B y = sin(2πx - πt) is the closest if we assume ω = π rather than 2π²
  Therefore, considering the approximations and potential errors in the given information, option B seems the most appropriate although not entirely correct. Option D represents a wave traveling in the negative x-direction.