A weight ω is suspended from the mid-point of a rope, whose ends are at the same level. In order to make the rope perfectly horizontal, the force applied to each of its ends must be:
less than ω
equal to 2ω
infinitely large
equal to ω
Solution:
For equilibrium of body, mg = 2Tcosθ ⇒ T = mg/2cosθ For string to be horizontal, θ → 90° ⇒ T = mg/2cosθ → ∞