0.5
0.7
0.6
0.8
Correct option is C. 0.6
In 1st situation
Vbρbg = Vsρw
Vs/Vb = ρb/ρw = 4/5.. (i)
here Vb is volume of block
Vs is submerged volume of block
ρb is density of block
ρw is density of water
Let ρo is the density of oil
Finally in equilibrium condition
Vbρbg = (Vb/2)ρog + (Vb/2)ρwg
ρb = (ρo + ρw)/2
⇒ ρo/ρw = 2ρb/ρw - 1 = 2(4/5) - 1 = 3/5 = 0.6