ABCD is a rectangle whose three vertices are B(4,0), C(4,3) and D(0,3). The length of one of its diagonals is?
25
5
3
4
Solution:
From the diagram we can see that AB=4units, BC=3units Using Pythagoras theorem, AC²=AB²+BC²=4²+3² AC²=16+9=25 Taking square root on both the sides, we get AC=5units.