ABCD is a trapezium of area 24.5 sq. cm. In it, AD∥BC, ∠DAB=90°, AD=10 cm and BC=4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. [Take π=22/7].

Given: AD=10cm BC=4cm Area of trapezium=24.5 cm²
Area of trapezium = (a+b)/2 × height
24.5 = (AD+BC)/2 × AB
24.5 = (10+4)/2 × AB
AB = 3.5cm
Radius = 3.5cm
Area of quadrant = Area of circle/4
Area of quadrant = (1/4) × π × r² = (22/7) × 3.5² × 0.25 = 9.625cm²
The area of shaded region = Area of trapezium – Area of given quadrant
The area of shaded region = 24.5 – 9.625 = 14.875 cm²