Account for the following: (i) Sulphur in vapour form exhibit paramagnetic behaviour. (ii) SnCl4 is more covalent than SnCl2. (iii) H3PO2 is a stronger reducing agent than H3PO3.
Solution:
(i) It is because sulphur in vapour form have unpaired electrons (ii) It is due to higher oxidation state (+4) of Sn in SnCl4 and it also has high polarising power (iii) It is because of two P−H bonds in H3PO2 whereas in H3PO3 only one P−H bond.