(NH4)2[TiCl6]
VOSO4
K3[Cu(CN)4]
K2Cr2O7
InK2Cr2O7, theCris in +6 oxidation state.Electronic configuration ofCr+6=3d0In(NH4)2[TiCl6],theTiis in+4oxidation state.Electronic configuration ofTi+4=3d0InVOSO4,Vis in+4oxidation state.Electronic configuration ofV+4=3d1It contains 1 unpaired electron.K3[Cu(CN)4]→Cu+:3d10VOSO4, due to the presence of one unpaired electron, is paramagnetic and coloured.Hence, option C is the answer.